What are the major products for reaction with cis-1-chloro-3-methylcyclopentane and trans-1-chloro-3-methylcyclopentane with #"OH"^(-)# in water at high temperature?

What type of reaction?

I predict an #"E2"# elimination because:

• The substrate is a secondary alkyl halide.
• The substrate has at least one β-hydrogen: possible elimination.
• The nucleophile (#"OH"^"-"#) is a strong base: possible elimination.
• There is (presumably) a high base concentration: favouring #"E2"#.
• Water is a polar protic solvent: favouring elimination.
• The high temperature favours elimination.

  cis-1-Chloro-3-methylcyclopentane

  The structure of the substrate is

  Elimination requires a trans arrangement of the β-hydrogen and the leaving group.

  We see appropriate β-hydrogens at #"C2"# and #"C5"#.

  Elimination of the hydrogen from #"C2"# forms 3-methylcyclopentene.

  Elimination of the hydrogen from #"C5"# forms 4-methylcyclopentene.

  These two isomers would probably be formed in roughly equal amounts.

  trans-1-Chloro-3-methylcyclopentane

  The structure of the substrate is

  Again, we see trans β-hydrogens at #"C2"# and #"C5"#.

  However, elimination will be slower in each case because of steric hindrance by the methyl group.

  Elimination of the hydrogen from #"C5"# will be faster than from #"C2"# because of its greater distance from the methyl group.

  Thus, the major product will be 4-methylcyclopentene.