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In the triangle ABC AB=12cm angle BAC=60 and ACB is 45 find the exact length of BC?

Answer 1

BC = #6sqrt(6)#

Angle #ABC = 180^o-(60^o +45^o)=75^o#

Using The Sine Rule:

#sinA/a=sinB/b=sinC/c#

#sin(60^o)/a=sin(45^o)/12=>a=(12sin(60^o))/sin(45^o)=((12sqrt(3))/2)/(sqrt(2)/2)=(12sqrt(3))/sqrt(2)=(12sqrt(6))/2=6sqrt(6)#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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