In triangle ABC, how do you solve the right triangle given Side AB=3 Side BC=4?
Using the pythagorean theorem you have
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To solve the right triangle given side AB = 3 and side BC = 4, you can use the Pythagorean theorem.

First, identify which sides are the legs and which is the hypotenuse. In a right triangle, the side opposite the right angle (which is side BC in this case) is the hypotenuse, and the other two sides are the legs.

Apply the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (BC) is equal to the sum of the squares of the lengths of the legs (AB and AC). So, you'll have:
( BC^2 = AB^2 + AC^2 )

Substitute the given values into the equation:
( 4^2 = 3^2 + AC^2 )

Solve for AC:
( 16 = 9 + AC^2 )
( AC^2 = 16  9 = 7 )
( AC = \sqrt{7} ) or approximately 2.65
So, the length of side AC is approximately 2.65.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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