How many grams of methane are produced from the complete reaction of 5.15 moles of carbon monoxide in the reaction #CO + 3H_2 -> H_2O + CH_4#?

Answer 1

It is revealed from the given balanced Eq that 1 mole of #CO # produces 1 mole #CH_4# when it reacts completely So 5.15 mole #CO # will produce 5.15 mole #CH_4# molar mass of #CH_4 = 16gmmol^-1# Mass of 1 mole #CH_4 = 16g# So mass of 5.15 mole #CH_4 = 5.15xx16=82.4g#

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Answer 2

Henry Antrim

The molar ratio of CO to CH₄ is 1:1 in this reaction. Therefore, 5.15 moles of CO will produce 5.15 moles of CH₄. To convert moles to grams, you need to use the molar mass of CH₄, which is approximately 16.05 g/mol. Multiplying the number of moles by the molar mass gives the mass in grams. So, 5.15 moles of CH₄ is equivalent to approximately 82.64 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How many grams of methane are produced from the complete reaction of 5.15 moles of carbon monoxide in the reaction #CO + 3H_2 -&gt; H_2O + CH_4#?

How many grams of methane are produced from the complete reaction of 5.15 moles of carbon monoxide in the reaction #CO + 3H_2 -> H_2O + CH_4#?