# How do you solve #sqrt3 sinx-cosx=1#?

Divide both sides by 2, use the identity:

and then solve for x.

Divide both sides of equation [1] by 2:

The left side of equation [2] is the same form as the right side of the following trigonometric identity:

Use the inverse sine function on both sides of equation [4]:

#x - pi/6 = { (pi/6 + 2npi), ((5pi)/6 + 2npi) :}#

#x = { (pi/3 + 2npi), (pi + 2npi) :}#

where n is any positive or negative integer including 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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