# How do you evaluate #(1+ 3i ) - ( 5+ 9i )#?

By signing up, you agree to our Terms of Service and Privacy Policy

Just separate real & imaginary parts & add/subtract them as follows

By signing up, you agree to our Terms of Service and Privacy Policy

To evaluate ((1 + 3i) - (5 + 9i)), you simply subtract the real parts and the imaginary parts separately.

Real part: (1 - 5 = -4)

Imaginary part: (3i - 9i = -6i)

So, the result is (-4 - 6i).

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you simplify #(4-6i)(2+3i)#?
- How do you simplify #3(cos(pi/6)+isin(pi/6))div4(cos((2pi)/3)+isin((2pi)/3))# and express the result in rectangular form?
- How do you simplify #(2-sqrt2i)/(3+sqrt6i)#?
- One solution of #x^3+(2-i)x^2+(-4-3i)x+(1+i)=0# is #x=1+i#. Find the only positive real solution for #x#?
- How do you simplify #(2+3i) (1-2i) #?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7