# How do you divide #(-5-3i) -: (7-10i)#?

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To divide complex numbers, you typically multiply the numerator and denominator by the complex conjugate of the denominator. In this case, the complex conjugate of (7-10i) is (7+10i). So, the calculation would be:

[ \frac{-5-3i}{7-10i} \times \frac{7+10i}{7+10i} ]

Expanding this expression, we get:

[ \frac{(-5-3i)(7+10i)}{(7-10i)(7+10i)} ]

[ = \frac{(-5 \times 7) + (-5 \times 10i) + (-3i \times 7) + (-3i \times 10i)}{(7 \times 7) + (7 \times 10i) + (-10i \times 7) + (-10i \times 10i)} ]

[ = \frac{-35 - 50i - 21i - 30i^2}{49 + 70i - 70i - 100i^2} ]

Since (i^2 = -1), we can simplify further:

[ = \frac{-35 - 50i - 21i + 30}{49 + 100} ]

[ = \frac{-5 - 71i}{149} ]

So, the result of dividing (-5-3i) by (7-10i) is (-\frac{5}{149} - \frac{71}{149}i).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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