How do you determine whether the function #g(x)=-x^2+3x+4# is concave up or concave down?

Answer 1

Two methods:

#g(x) = -x^2+3x+4#
#g'(x) = -2x+3#
#g''(x) = -2#
Since #g''(x)# is always negative, the graph of #g# is concave down on the domain of #g#. Which is to say: #g# is concave down on #(-oo, oo)#.
Using algebra, the graph of this quadratic is a parabola. Since the coefficient of #x^2# is negative, the parabola opens downward. It is concave down.
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Answer 2
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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