# Given the function #f(x)= 1/12x^4 + 1/6x^3-3x^2-2x+1# how do you find any points of inflection and determine where the curve is concave up or down?

So in U the curve is concave up, and in D the curve is concave down

By signing up, you agree to our Terms of Service and Privacy Policy

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the first and second derivative of #(lnx)^(x)#?
- What are the points of inflection, if any, of #f(t) = 4t^3 + 3t^2 - 6t +1 #?
- For what values of x is #f(x)= -5x^3+x^2+4x-12 # concave or convex?
- How many points of inflection does the function #f(x)=x^7-x^2# have?
- How do you sketch #f(x,y)=arcsin(x^2+y^2-2)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7