What are the valence electrons in #MgCl^+#, #CO_2#, and #HF#?

Answer 1

Well magnesium is an #"alkaline earth"#, i.e. a #"Group 2 metal cation"#....

And so for #MgCl^+#; you possibly meant to write #MgCl_2#, i.e. #Mg^(2+) + 2xxCl^-#.
For #CO_2#, we have #4+6+6# valence electrons to distribute; i.e. 8 electron pairs:
#:stackrel(..)O=C=stackrel(..)O:#
And for hydrogen fluoride, we have #1+7# valence electrons, i.e. 4 electron pairs...........
#H-F#.
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Answer 2

The number of valence electrons in MgCl^+ is 2, in CO2 it is 16, and in HF it is 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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