What are the structures of the isomers of dichloropropane?

Answer 1

See below.

Start with a #"Cl"# at one end and then put a second #"Cl"# in every possible position.

This provides us with

1. #"CH"_3"CH"_2"CHCl"_2#, 1,1-dichloropropane

and

2. #"CH"_3"CHClCH"_2"Cl"#, 1,2-dichloropropane

additionally

3. #"ClCH"_2"CH"_2"CH"_2"Cl"#, 1,3-dichloropropane
Now put a #"Cl"# on the middle carbon and put the second #"Cl"# in all possible locations.

It yields just one additional isomer.

#"CH"_3"CCl"_2"CH"_3#, 2,2-dichloropropane

The four isomers of dichloropropane are shown there.

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Answer 2

The structures of the isomers of dichloropropane are:

  1. 1,2-dichloropropane (structural formula: CH3CHClCH2Cl)
  2. 1,3-dichloropropane (structural formula: CH3CHClCH2Cl)
  3. 2,2-dichloropropane (structural formula: CH3CHClCH2Cl)
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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