How do you find two numbers such that their sum is #9# and the difference of their squares is also #9#?
4 and 5 (By trial and error)
You should try numbers such as 1 and 2 (their sum is 3 not 9), or 3 and 4 (their sum is 7 not 9). The other must is the difference of their squares. Therefore, you can reach your conclusion.
Your numbers are 4 and 5.
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The numbers are
Check:
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Let the two numbers be (x) and (y). We are given that their sum is 9, so (x + y = 9), and the difference of their squares is 9, so (x^2 - y^2 = 9).
From the first equation, we can express (y) in terms of (x): (y = 9 - x).
Substitute (y) in terms of (x) into the second equation:
(x^2 - (9 - x)^2 = 9)
Expand the squared term:
(x^2 - (81 - 18x + x^2) = 9)
Simplify:
(x^2 - 81 + 18x - x^2 = 9)
Combine like terms:
(18x - 81 = 9)
Add 81 to both sides:
(18x = 90)
Divide by 18:
(x = 5)
Now, substitute (x = 5) back into (y = 9 - x):
(y = 9 - 5)
(y = 4)
So, the two numbers are 5 and 4.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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