How do you factor #3h^2 + 19h + 20#?

Answer 1

#f(h) = 3h^2+19h+20#

Let's apply the AC Method in a unique way.

#A=3#, #B=19#, #C=20#

Look for a factorization of #AC=3*20=60# into a pair of factors whose sum is #B=19#.

The pair #B1=4#, #B2=15# works.

Then for each of the combinations #A#, #B1# and #A#, #B2#, divide by the #"HCF"# (highest common factor) to get the coefficients of a factor of #f(h)#...

#(A, B1) = (3, 4)# #("HCF 1")##rarr## (3, 4)##rarr## (3h+4)# #(A, B2) = (3, 15)# #("HCF 3")##rarr##(1, 5)##rarr##(h+5)#

So #f(h) = 3h^2+19h+20 = (3h+4)(h+5)#

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Answer 2

Jace Anderson

To factor the expression $3h^2 + 19h + 20$ , find two numbers that multiply to $3 \times 20$ (which is $60$ ) and add to $19$ . The numbers are $15$ and $4$ . Then, rewrite the middle term as the sum of these two terms: $19h = 15h + 4h$ . Now, factor by grouping:

$3h^2 + 15h + 4h + 20$

Factor by grouping:

$3h(h + 5) + 4(h + 5)$

Factor out the common factor $h + 5$ :

$(3h + 4)(h + 5)$

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.