What is the speed of an object that travels from #( 2,-5,6 ) # to #( 2, -4 ,1 ) # over #2 s#?

Answer 1

#2.55units//s#

First find the distance between the 2 given points by using the normal Euclidean metric in #RR^3#.
#therefored[(2,-5,6);(2,-4,1)]=sqrt((2-2)^2+(-5-(-4))^2+(6-1)^2)#
#=sqrt26#.

Now apply the definition of speed, the rate of change in distance, to get

#v=x/t=sqrt26/2=2.55units//s#
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Answer 2

To find the speed of an object traveling from point (2,5,6) (2, -5, 6) to point (2,4,1) (2, -4, 1) over 2 seconds, calculate the distance between the two points using the distance formula in 3D space:

Distance=(x2x1)2+(y2y1)2+(z2z1)2\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}

Then, divide the distance by the time taken, which is 2 seconds, to find the speed.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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