What is the perimeter of a triangle with corners at #(7 ,3 )#, #(1 ,5 )#, and #(2 ,4 )#?

Answer 1

Perimeter is #12.84#.

Let us find the sides of triangle formed by #(7,3)#, #(1,5)# and #(2,4)#. This will be surely distance between pair of points, which is

#a=sqrt((1-7)^2+(5-3)^2)=sqrt(36+4)=sqrt40=6.3246#

#b=sqrt((2-1)^2+(4-5)^2)=sqrt(1+1)=sqrt2=1.4142# and

#c=sqrt((2-7)^2+(4-3)^2)=sqrt(25+1)=sqrt26=5.099#

Hence perimeter is #6.3246+1.4142+5.099=12.8378# or say #12.84#.

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Answer 2

Aaliyah Anderson

To find the perimeter of a triangle with corners at (7, 3), (1, 5), and (2, 4), you need to calculate the sum of the lengths of its three sides. Use the distance formula to find the distance between each pair of points. Then, add these distances together to get the perimeter.

The distance between (7, 3) and (1, 5) is √((7-1)^2 + (3-5)^2) = √36 + 4 = √40. The distance between (1, 5) and (2, 4) is √((1-2)^2 + (5-4)^2) = √1 + 1 = √2. The distance between (2, 4) and (7, 3) is √((2-7)^2 + (4-3)^2) = √25 + 1 = √26.

The perimeter is the sum of these distances: √40 + √2 + √26.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.