Objects A and B are at the origin. If object A moves to #(3 ,6 )# and object B moves to #(1 ,-4 )# over #1 s#, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

Answer 1

Charles Aeschliman

The relative velocity is #== <-2, -10> ms^-1#

The absolute velocity of #A# is #v_A=1/1<3,6> = <3,6> ms^-1#

The absolute velocity of #B# is #v_B=1/1<1,-4> = <1,-4> ms^-1#

The relative velocity of #B# with respect to #A# is

#v_(B//A) =v_B-v_A= <1,-4> - <3,6>#

#= <(1-3), (-4-6)> #

#= <-2, -10> ms^-1#

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Answer 2

Charles Aeschliman

To find the relative velocity of object B from the perspective of object A, subtract the velocity of object A from the velocity of object B.

Velocity of object A = (3 - 0) / 1 = 3 m/s in the x-direction and (6 - 0) / 1 = 6 m/s in the y-direction. Velocity of object B = (1 - 0) / 1 = 1 m/s in the x-direction and (-4 - 0) / 1 = -4 m/s in the y-direction.

Relative velocity of object B from the perspective of object A: x-direction: 1 m/s - 3 m/s = -2 m/s y-direction: -4 m/s - 6 m/s = -10 m/s

Therefore, the relative velocity of object B from the perspective of object A is -2 m/s in the x-direction and -10 m/s in the y-direction.

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