If an object is moving at #20 m/s# over a surface with a kinetic friction coefficient of #u_k=3/g#, how much time will it take for the object to stop moving?

Answer 1

#t=20 s#

#F_f=k*m*g# #F_f=3/cancel(g)*m*cancel(g)# #F_f=m# #F=m*a" The Newton's law"# #m=m*a# #a=1 m/s^2# #v_l :"last velocity ; "v_i:" initial velocity"# #v_l=v_i-a*t# #v_l=0 " when object is stops"# #0=20-1*t# #t=20 s#

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Answer 2

Julia Aguilar

To find the time it takes for the object to stop moving, you can use the equation for kinetic friction: $F_{\text{friction}} = \mu_k \times F_{\text{normal}}$ . First, calculate the frictional force using this equation. Then, apply Newton's second law ( $F = ma$ ) to find the acceleration of the object. Once you have the acceleration, you can use the equation $v = u + at$ to find the time it takes for the object to stop, where $v$ is the final velocity (0 m/s), $u$ is the initial velocity (20 m/s), $a$ is the acceleration, and $t$ is the time.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.