Identify the quadrant or quadrants in which an angle A in standard position must be if csc A > 0 and tan A < 0?

Answer 1
On the trig unit circle, since tan x < 0, then x should be in Quadrant II or Quadrant IV. Since #csc = 1/sin x > 0# -> sin x > 0, then x should be in Quadrant II.
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Answer 2

Angle A must be located in Quadrant II, as csc A > 0 means that the sine function (and hence csc A) is positive, and tan A < 0 means that the tangent function is negative. In Quadrant II, both sine and tangent are positive, while cosine is negative.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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