Need insights into the question "How many moles of O_2 are required to generate 18 moles of H_2O in the reaction 2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O? " Check out the answers and our thorough explanations regarding this question.

How many moles of O_2 are required to generate 18 moles of H_2O in the reaction 2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O?  | HIX Tutor

<mathjax>#18mol H_2 O x ((25 molO_2)/ (18molH_2 O)) = 25 mol O_2#</mathjax>
Moles of water cancel, leaving you with moles of Oxygen. 
Factor out 18/18=1. 
25 x 1 = 25

<mathjax>#18mol H_2 O x ((25 molO_2)/ (18molH_2 O)) = 25 mol O_2#
Moles of water cancel, leaving you with moles of Oxygen. 
Factor out 18/18=1. 
25 x 1 = 25

You will need 25 moles, but this is not based on the equation alone.

Caleb Adams

To generate 18 moles of H2O, you need 18 moles of O2, as the stoichiometric coefficient for O2 in the reaction is 25.

How many moles of #O_2# are required to generate 18 moles of #H_2O# in the reaction #2C_8H_18 + 25O_2 -&gt; 16CO_2 + 18H_2O#?

How many moles of #O_2# are required to generate 18 moles of #H_2O# in the reaction #2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O#?