How many moles of iron are in 0.067 gram sample of iron oxide?

Answer 1

Well if its #"ferric oxide"#..........

#"Ferric oxide"#, #Fe_2O_3#, has a molar mass of #159.69*g*mol^-1#.

#"Moles of ferric oxide"=(0.067*g)/(159.69*g*mol^-1)=4.20xx10^-4mol#.

Of course it could be #"ferrous oxide"#, #FeO#, or another iron oxide, so I don't think that this question was well-proposed.

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Answer 2

Ellie Andrews

The formula to calculate the moles of iron in the iron oxide sample is moles = mass / molar mass. Substituting the values, you get moles = 0.067 grams / 71.85 grams per mole moles ≈ 0.000933 moles. Based on this, you can calculate the number of moles of iron in the 0.067 gram sample of iron oxide. The molar mass of FeO is approximately 71.85 grams per mole.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.