How many helium atoms are in a helium blimp containing 494 kg of helium?

Answer 1

#7.44*10^28# atoms

Step 1: calculate how the number of moles using the molar mass. The molar mass of helium = #4.00# g/mol. This means that 1 mole of helium atoms weighs 4 gram.

In this case you have #494# kg which is #494.000# grams. How many moles is this?

#(494.000 color(red)cancel(color(black)(gram)))/ (4.00 color(red)cancel(color(black)(gram))/(mol)) = 123.500 mol#

Step 2 : calculate the number of atoms using Avogadro's constant. Avogadro's constant states that there are #6.02*10^23# atoms in one mole of any element.

What is 123.500 moles of atoms?

#6.02*10^23 "atoms"/color(red)cancel(color(black)((mol))) * 123.500 color(red)cancel(color(black)(mol)) = 7.44*10^28 "atoms"#

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Answer 2

Cooper Anderson

In order to determine how many helium atoms are in a helium blimp, first determine how many moles of helium there are using the molar mass of helium (4.0026 g/mol). Next, convert moles to atoms using Avogadro's number (6.022 × 10^23 atoms/mol). This would give you: 494 kg × 1000 g/kg ÷ 4.0026 g/mol ÷ (6.022 × 10^23 atoms/mol) ≈ 8.20 × 10^27 helium atoms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.