How many helium atoms are in a helium blimp containing 494 kg of helium?

Question

Luna Chen · Accepted Answer

#7.44*10^28# atoms

Step 1: calculate how the number of moles using the molar mass. The molar mass of helium = #4.00# g/mol. This means that 1 mole of helium atoms weighs 4 gram. In this case you have #494# kg which is #494.000# grams. How many moles is this? #(494.000 color(red)cancel(color(black)(gram)))/ (4.00 color(red)cancel(color(black)(gram))/(mol)) = 123.500 mol# Step 2 : calculate the number of atoms using Avogadro's constant. Avogadro's constant states that there are #6.02*10^23# atoms in one mole of any element. What is 123.500 moles of atoms? #6.02*10^23 "atoms"/color(red)cancel(color(black)((mol))) * 123.500 color(red)cancel(color(black)(mol)) = 7.44*10^28 "atoms"#

Cooper Anderson · Answer

undefined In order to determine how many helium atoms are in a helium blimp, first determine how many moles of helium there are using the molar mass of helium (4.0026 g/mol). Next, convert moles to atoms using Avogadro's number (6.022 × 10^23 atoms/mol). This would give you: 494 kg × 1000 g/kg ÷ 4.0026 g/mol ÷ (6.022 × 10^23 atoms/mol) ≈ 8.20 × 10^27 helium atoms.