How is angular speed at perihelion calculated?

Answer 1

Angular speed, from orbital speed, at perihelion: At perihelion and aphelion, angular acceleration is 0. So, angular speed is simply v/r.
Answer:1.18E-05 deg/s = 1.02 deg/day

The Earth rotates at its maximum angular speed at perihelion, where v = 30.29 km/s and r = 1.471 E+08 km. The minimum at aphelion, which is almost 0.94 deg/day, can be easily computed. The average angular speed is 0.9856 deg/day.

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Answer 2

Hailey Alvarez

The following formula can be used to determine the angular speed at perihelion: $\omega = \sqrt{\frac{G(M + m)}{r^3}}$ Where: - $\omega$ is the angular speed; - $G$ is the gravitational constant (roughly $6.674 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2}$ ); - $M$ is the mass of the larger body (e.g., the Sun); - $m$ is the mass of the smaller body (e.g., a planet); - $r$ is the distance between the centers of the two bodies at perihelion.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.