How do you solve #5(a-1)-15=3(a+2)+4#?

Answer 1

#a=15#

First, use the distributive property on the parentheses and combine like terms #5(a-1)-15=3(a+2)+4# #5a-5-15=3a+6+4# #5a-20=3a+10#

Then, subtract 3a from both sides #2a-20=10#

Finally, solve for a #2a-20=10# #a=15#

Now that we know what a is, we can substitute for a in the original equation #5(15-1)-15=3(15+2)+4# #75-5-15=45+6+4# #55=55# (correct)

We can now conclude that a is equal to 15

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Answer 2

Eva Abramson

To solve the equation 5(a-1)-15=3(a+2)+4, you would first distribute the numbers outside the parentheses:

5a - 5 - 15 = 3a + 6 + 4

Next, combine like terms on both sides of the equation:

5a - 20 = 3a + 10

Then, move all the terms involving the variable "a" to one side of the equation:

5a - 3a = 10 + 20

Finally, simplify and solve for "a":

2a = 30

a = 15

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.