How do you solve #-2n = 8- n#?

Answer 1

Ethan Adkins

See a solution process below:

First, add #color(red)(n)# to each side of the equation to isolate the #n# term while keeping the equation balanced:

#-2n + color(red)(n) = 8 - n + color(red)(n)#

#-2n + color(red)(1n) = 8 - 0#

#(-2 + color(red)(1))n = 8#

#-1n = 8#

#-n = 8#

Now, multiply each side of the equation by #color(red)(-1)# to solve for #n# while keeping the equation balanced:

#color(red)(-1) xx -n = color(red)(-1) xx 8#

#n = -8#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.