How do you simplify #sqrt88 * sqrt33#?

Since is a product, conmutativity allows us to reorganize it.

Now, increase:

Reorganize:

To simplify $\sqrt{88} \times \sqrt{33}$, you can use the property of square roots which states that the product of two square roots is equal to the square root of the product of their radicands.

Therefore,

$\sqrt{88} \times \sqrt{33} = \sqrt{88 \times 33}$

Now, calculate the product of 88 and 33:

$88 \times 33 = 2904$

So,

$\sqrt{88} \times \sqrt{33} = \sqrt{2904}$

To simplify $\sqrt{2904}$, find the prime factorization of 2904:

$2904 = 2^3 \times 3 \times 11^2$

Now, take out pairs of the same numbers to simplify the square root:

$\sqrt{2904} = \sqrt{2^2 \times 3 \times 11^2}$

$\sqrt{2904} = 2 \times 11 \times \sqrt{3}$

$\sqrt{2904} = 22 \sqrt{3}$

So,

$\sqrt{88} \times \sqrt{33} = 22 \sqrt{3}$