How do you simplify #7/8*3 1/5#?

Answer 1

Kennedy Adams

We first make an improper fraction of #3 1/5#

#3 1/5=3xx5/5+1/5=(15+1)/5=16/5#

We now have #7/8xx16/5=(7xx16)/(8xx5)#

We can only cancel out a #8#: #(7xx2xxcancel8)/(cancel8xx5)=(7xx2)/(5)=14/5# This can be written as #2 4/5#

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Answer 2

Hazel Anglin

To simplify $\frac{7}{8} \times 3 \frac{1}{5}$ , first convert the mixed number $3 \frac{1}{5}$ to an improper fraction, which equals $\frac{16}{5}$ . Then multiply $\frac{7}{8}$ by $\frac{16}{5}$ . Multiply the numerators (7 and 16) to get 112, and multiply the denominators (8 and 5) to get 40. So, $\frac{7}{8} \times 3 \frac{1}{5} = \frac{112}{40}$ . Simplify this fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 8. After simplification, you get $\frac{14}{5}$ . So, $\frac{7}{8} \times 3 \frac{1}{5}$ simplifies to $\frac{14}{5}$ .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.