How do you multiply #(x+1)(x+4)#?

Answer 1

Nathan Axel

#x^2+5x+4#

first multiply #x# with #(x+4)# and then #1# with again #(x+4)# so #x^2+4x+x+4# #x^2+5x+4#

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Answer 2

Hazel Anglin

Use FOIL to help find:

#(x+1)(x+4) = x^2+5x+4#

If you find it helpful, you can use the FOIL mnemonic to help you identify which terms to combine.

#(x+1)(x+4) = overbrace((x*x))^"First" + overbrace((x*4))^"Outside"+overbrace((1*x))^"Inside"+overbrace((1*4))^"Last"#

#=x^2+4x+x+4 = x^2+5x+4#

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Answer 3

Genesis Allen

To multiply (x+1)(x+4), you can use the distributive property or the FOIL method.

(x+1)(x+4) = x(x) + x(4) + 1(x) + 1(4) = x^2 + 4x + x + 4 = x^2 + 5x + 4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.