How do you find the square root of 15?

Answer 1

#sqrt(15)# is not simplifiable.

We can find rational approximations #31/8#, #244/63#

#15=3xx5# has no square factors, so #sqrt(15)# cannot be simplified.
It is not expressible as a rational number. It is an irrational number a little less than #4#.
Since #15 = 4^2-1# is of the form #n^2-1#, #sqrt(15)# has a fairly simple continued fraction expansion:
#sqrt(15) = [3;bar(1,6)] = 3+1/(1+1/(6+1/(1+1/(6+1/(1+1/(6+1/(1+...)))))))#
We can truncate this continued fraction expansion early to get rational approximations to #sqrt(15)#.

As an illustration:

#sqrt(15) ~~ [3;1,6,1] = 3+1/(1+1/(6+1/1)) = 3+1/(1+1/7) = 3+7/8 = 31/8 = 3.875#
#sqrt(15) ~~ [3;1,6,1,6,1] = 3+1/(1+1/(6+1/(1+1/(6+1/1)))) = 3+1/(1+1/(6+1/(1+1/7)))#
#= 3+1/(1+1/(6+7/8)) = 3+1/(1+8/55) = 3+55/63 = 244/63 = 3.bar(873015)#

In actuality:

#sqrt(15) ~~ 3.87298334620741688517#
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Answer 2

To find the square root of 15, you can use a calculator or long division method. The approximate value of √15 is 3.87298.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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