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How do you find the product (4-x)(4+x)? | HIX Tutor

<blockquote>
<mathjax>#"these are the factors of a "color(blue)"difference of squares"#</mathjax>
<mathjax>#•color(white)(x)a^2-b^2=(a-b)(a+b)#</mathjax>
<mathjax>#"here "a=4" and "b=x#</mathjax>
<mathjax>#rArr(4-x)(4+x)=4^2-x^2=16-x^2#</mathjax>
</blockquote>

<blockquote>
<mathjax>#"these are the factors of a "color(blue)"difference of squares"#
<mathjax>#•color(white)(x)a^2-b^2=(a-b)(a+b)#
<mathjax>#"here "a=4" and "b=x#
<mathjax>#rArr(4-x)(4+x)=4^2-x^2=16-x^2#
</blockquote>

Nathan Axel

To find the product of \( (4 - x) \) and \( (4 + x) \), you can use the distributive property or the FOIL method. Distribute each term in the first expression \( (4 - x) \) to each term in the second expression \( (4 + x) \), then simplify the result. 

\[ (4 - x)(4 + x) = 4 \times 4 + 4 \times x - x \times 4 - x \times x \]

\[ = 16 + 4x - 4x - x^2 \]

\[ = 16 - x^2 \]

How do you find the product #(4-x)(4+x)#?