How do you find the product #2j^2(5j^3-15j^2+2j+2)#?

Answer 1

Kennedy Adams

#2j^2(-5j^3+15j^2+4j+2)#

#-2j^2(5j^3-15j^2+2j+2)#

#:.=-10j^5+30j^4-4j^3-4j^2#

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Answer 2

Eva Adamson

To find the product 2j^2(5j^3 - 15j^2 + 2j + 2), you distribute the term 2j^2 to each term inside the parentheses and then simplify the expression:

2j^2 * 5j^3 = 10j^(2+3) = 10j^5 2j^2 * (-15j^2) = -30j^(2+2) = -30j^4 2j^2 * 2j = 4j^(2+1) = 4j^3 2j^2 * 2 = 4j^2

So, the product becomes: 10j^5 - 30j^4 + 4j^3 + 4j^2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.