# How do you find the intervals of increasing and decreasing using the first derivative given #y=xsqrt(16-x^2)#?

The interval of increasing is

The intervals of decreasing are

The derivative is what we require.

So,

That is

We are able to construct the variation chart.

plot{xsqrt(16-x^2) [-16.02, 16.01, -8.01, 8.01]}

By signing up, you agree to our Terms of Service and Privacy Policy

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the difference between a critical point and a stationary point?
- How do you find the value of c guaranteed by the Mean Value Theorem for #f(x)=(2x)/(x^2+1)# on the interval [0,1]?
- How do you find the critical numbers for #h(t) = (t^(3/4)) − (9*t^(1/4))# to determine the maximum and minimum?
- How do use the first derivative test to determine the local extrema #f(x) = xsqrt(25-x^2)#?
- Is #f(x)=3x^2-x+4# increasing or decreasing at #x=2#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7