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How do you find the derivative of  1/t^2? | HIX Tutor

Given -
<blockquote>
<mathjax>#y=1/t^2#</mathjax>
</blockquote>
It can be written as -
<blockquote>
<mathjax>#y=t^-2#</mathjax>
</blockquote>
Then apply the differentiation rule to differentiate
<blockquote>
<mathjax>#dy/dx=-2t^-3#</mathjax>
</blockquote>
This can be written as -
<blockquote>
<mathjax>#dy/dx=-2/t^3#</mathjax>
</blockquote>

Given -
<blockquote>
<mathjax>#y=1/t^2#
</blockquote>
It can be written as -
<blockquote>
<mathjax>#y=t^-2#
</blockquote>
Then apply the differentiation rule to differentiate
<blockquote>
<mathjax>#dy/dx=-2t^-3#
</blockquote>
This can be written as -
<blockquote>
<mathjax>#dy/dx=-2/t^3#
</blockquote>

Emilia Aguilar

To find the derivative of \( \frac{1}{t^2} \), you apply the power rule for differentiation, which states that the derivative of \( x^n \) with respect to \( x \) is \( nx^{n-1} \). Thus, the derivative of \( \frac{1}{t^2} \) is \( -2t^{-3} \).

How do you find the derivative of # 1/t^2#?