# How do you find the center of the circle that is circumscribed about the triangle with vertices (0,-2), (7,-3) and (8,-2)?

The center is at

The point where the perpendicular bisector of the triangle's three sides intersects is where the center is located.

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To find the center of the circle circumscribed about a triangle, you need to find the intersection point of the perpendicular bisectors of any two sides of the triangle.

- Find the midpoints of any two sides of the triangle.
- Find the slopes of these two sides.
- Find the negative reciprocal of these slopes to get the slopes of the perpendicular bisectors.
- Use the midpoint and the slope of each side to write the equations of the perpendicular bisectors.
- Solve these equations simultaneously to find the point of intersection, which is the center of the circumscribed circle.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- Convert #x^2+2y^2-2x+8y-11=0# to standard form of equation for ellipse and find its vertices, focii and latus rectum?
- How do you find the center and radius of a circle using a polynomial #(x^2) + (y^2) + 6x - 4y = 12#?
- What is the standard form of the equation of a circle with centre (3,-1) and which touches the y-axis?

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