How do you factor #x^2-28x+196#?

Answer 1

Abigail Allen

#(x-14)^2#

#"note that "-14xx-14=196" and -14 +(-14)=-28"#

#rArrx^2-28x+196#

#=(x-14)(x-14)#

#=(x-14)^2#

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Answer 2

Isaiah Anthony

#(x - 14) (x - 14)#

#x^2 - 28x + 196#

This is a quadratic equation, hence there are 2 factors..

When finding factors, you need to have two numbers, that will multiply themselves to give the constant and then add or subtract themselves to give the coefficient of #x#..

What am referring to is #-28x# and #+196#

Hence we have #14# as the factor;

#-> +196 = - 14 xx - 14#

#-> -28x = - 14x + (- 14x)#

Hence Imputing in the main equation we have..

#x^2 - 28x + 196#

#x^2 - 14x - 14x + 196#

#(x^2 - 14x) (-14x + 196)#

Extract the common factor!

#color(blue)x(x - 14) color(blue)(- 14)(x - 14)#

Separating the factors!

#(x - 14) color(blue)((x - 14)#

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Answer 3

Abigail Allen

To factor $x^2 - 28x + 196$ , you can use the factoring method for trinomials. This expression can be factored as $(x - 14)^2$ , since $14 \times 14 = 196$ and $2 \times 14 = 28$ .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.