How do you evaluate #abs(-8+11-4)+abs(4+7)#?

Answer 1

See a solution process below:

Examine the following expressions in the absolute value function first:

#abs(-8 + 11 - 4) + abs(4 + 7) =>#
#abs(3 - 4) + abs(11) =>#
#abs(-1) + abs(11)#

Using the absolute value function, any term can be converted to a non-negative form.

Using the absolute value function, we can now evaluate the expression as follows:

#1 + 11 => 12#
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Answer 2

12

Note: Absolute values essentially means to remove any negative sign within the signs - or to think of all numbers as positives within the signs.

So,

#|-8+11-4| + |4+7|#
#=|-12+11|+|4+7| #
#=|-1|+|11|#
#=1+11#
#=12#
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Answer 3

To evaluate abs(8+114)+abs(4+7) \text{abs}(-8 + 11 - 4) + \text{abs}(4 + 7) , follow these steps:

  1. Simplify within each absolute value: abs(1)+abs(11) \text{abs}(-1) + \text{abs}(11)
  2. Calculate the absolute values: 1+11 1 + 11
  3. Add the results: 1+11=12 1 + 11 = 12

So, abs(8+114)+abs(4+7)=12 \text{abs}(-8 + 11 - 4) + \text{abs}(4 + 7) = 12 .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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