How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#?

Answer 1

Nathan Axel

#2xy divide {2x^2}/y#

by rewriting as a multiplication,

#=2xy cdot {y}/{2x^2}={2xy^2}/{2x^2}#

by cancelling #2x#,

#={y^2}/{x}#

I hope that this was helpful.

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Answer 2

Jameson Allen

To divide and reduce the expression 2xy ÷ (2x^2/y) to the lowest terms, we can simplify it as follows:

First, we can rewrite the expression as a multiplication problem by multiplying the numerator by the reciprocal of the denominator:

2xy * (y/2x^2)

Next, we can cancel out common factors between the numerator and denominator:

(2xy * y) / (2x^2)

Simplifying further, we have:

2xy^2 / 2x^2

Now, we can cancel out the common factor of 2:

xy^2 / x^2

Finally, we can simplify by dividing the variables:

y^2 / x

Therefore, the expression 2xy ÷ (2x^2/y) reduces to y^2 / x in its lowest terms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.