By how much would the value of the following expression change if the absolute value parenthesis is changed to a regular one?: #|3-5*(7-2)|+5*(2-3)#

Answer 1

Changes by 44

In terms of absolute value

#abs(3-5xx(7-2))+5xx(2-3)#
#abs(3-5xx5)+5xx(-1)#
#abs(3-25)-5#
#abs(-22)-5#
#22-5=17#

Absent absolute value

#(3-5xx(7-2))+5xx(2-3)#
#(3-5xx5)+5xx(-1)#
#(3-25)-5#
#(-22)-5=-27#

Distinction

#17-(-27)=44#
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Answer 2

To find out how much the value of the expression changes when the absolute value parentheses are changed to regular parentheses, evaluate the expression with both scenarios:

Original expression with absolute value: [ |3-5*(7-2)| + 5*(2-3) ]

Evaluate the expression inside the absolute value first: [ |3-5*(7-2)| = |3-5*5| ] [ = |3-25| ] [ = |-22| ] [ = 22 ]

Now, evaluate the entire expression: [ |3-5*(7-2)| + 5*(2-3) = 22 + 5*(-1) ] [ = 22 - 5 ] [ = 17 ]

Expression with regular parentheses: [ (3-5*(7-2)) + 5*(2-3) ]

Evaluate inside the parentheses first: [ 3-5*(7-2) = 3-5*5 ] [ = 3-25 ] [ = -22 ]

Now, evaluate the entire expression: [ (3-5*(7-2)) + 5*(2-3) = -22 + 5*(-1) ] [ = -22 - 5 ] [ = -27 ]

The change in value is: [ 17 - (-27) = 17 + 27 = 44 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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