An object with a mass of #4 kg# is moving at #7 m/s# over a surface with a kinetic friction coefficient of #2 #. How much power will it take to accelerate the object at #4 m/s^2?

Answer 1

The power is #=660.8W#

The normal reaction is #N=mg=4gN#

The frictional force

#F_r=mu_k.N#
#F_r=2*4g N#
Let the force necessary to accelerate the object be #F#

Then,

#F=F_r+m*a#
#=8g+4*4#
#=94.4N#

The power is

#P=Fv#
#=94.4*7#
#=660.8W#
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Answer 2

To calculate the power required to accelerate the object at 4 m/s^2, you first need to find the net force acting on the object using Newton's second law (F = ma), where m is the mass of the object and a is the acceleration. Once you have the net force, you can calculate the power using the equation: Power = Force × Velocity.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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