A sphere is moving around in the air. If the moment of inertia is 10 Kg m2 and a radius of 1m. What is its mass?

Answer 1

Sebastian Acosta

The mass is #15" kg"#

The moment of inertia of a solid sphere is:

#I=2/3mr^2#

The radius of the sphere is #r=1m#.

The moment of inertia of the sphere is #I=10kgm^2#

The mass of the sphere is:

#m=3/2*I*1/r^2=3/2*10*1/1=color(red)(15" kg"#

I hope that helps!

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Answer 2

Elena Albarran

The moment of inertia of a sphere is given by the formula $I = \frac{2}{5} m r^2$ , where $m$ is the mass of the sphere and $r$ is the radius. Rearranging the formula to solve for mass, we have $m = \frac{5I}{2r^2}$ . Substituting the given values, the mass of the sphere would be $\frac{5 \times 10}{2 \times 1^2} = \frac{50}{2} = 25$ kg.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.