A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

Answer 1

Julia Aguilar

The change in centripetal force is #=0.22N#

Centripetal force is what

#F=(mv^2)/r#

#m=mass=9kg#

#v=0.18ms^-1#

The centripetal force fluctuation is

#DeltaF=F_2-F_1#

#F_1=9*0.18^2/0.32=0.91N#

#F_2=9*0.18^2/0.42=0.69N#

#DeltaF=0.91-0.69=0.22N#

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Answer 2

Benjamin Asiedu

To calculate the change in centripetal force, we need to first find the original and final centripetal forces using the formulas:

Centripetal force = (mass * velocity^2) / radius

Using the original radius of 32 cm: Centripetal force_initial = (9 kg * (18 cm/s)^2) / 32 cm

Using the final radius of 42 cm: Centripetal force_final = (9 kg * (18 cm/s)^2) / 42 cm

Then, we find the difference between the final and initial centripetal forces:

Change in centripetal force = Centripetal force_final - Centripetal force_initial

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.