Given a volume of gas at specified temperature and pressure, how does volume evolved if BOTH pressure and temperature are DOUBLED?

Answer 1

Should not the volume remain constant.....?

We gots #V_1=(nRT)/P#

....and #V_2=(nR*cancel2T)/(cancel2*P)=(nRT)/P=V_1# as required....and so the expansive effect of temperature is compensated by the compressive effect of pressure.....and volume remains constant.

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Answer 2

Wyatt Adkins

According to the ideal gas law, $PV = nRT$ , where $P$ is pressure, $V$ is volume, $n$ is the number of moles of gas, $R$ is the gas constant, and $T$ is temperature in Kelvin.

When both pressure and temperature are doubled while keeping the number of moles and the gas constant constant, the volume of the gas will also double. This is because according to the ideal gas law, when pressure and temperature change proportionally (in this case, they both double), the volume of the gas will change proportionally as well. Therefore, the volume of the gas will double.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.