# Madelyn Adams

Butler University

Trigonometry

Trigonometry teacher | Verified Expert

I am a Trigonometry specialist, holding a degree from Butler University. With a passion for mathematics, I've honed my expertise in Trigonometry to guide students through its complexities. My journey through Butler University equipped me with comprehensive knowledge and effective teaching strategies. I strive to foster a deep understanding of Trigonometry, helping students navigate its intricacies with confidence. Whether unraveling triangles or mastering trigonometric functions, I'm dedicated to empowering students to excel in this field. Join me on the path to mathematical mastery at Butler University's tutoring platform.

## Questions

- How do you simplify 1/(tanx+cotx)?
- How do I simplify cosx(secx+cscx)?
- What is the value of θ in tan(7θ+10)=1/tan(5θ-4)?
- Use the sum and difference identities to find the exact value of tan 105?
- Please solve q 35? Actually I can't understand the step that is tick marked
- How do I verify the trigonometric identity?
- How do you solve #2cos^2x-5cosx+3=0#?
- B is on a bearing 36 degrees from A and 8.4km from A. C is on a bearing of 147 degrees from A and 13.2km from A. How to find: (i) BC? (ii) the bearing of C from B?
- What is the value of cos^2 pi?
- What are the solution in the interval [0, 2pie]? sec^2x-tan^2x=0
- How do i solve for a right triangle?
- If tanx=-3/4 and 3Π/2<x<2Π,then value of sin2x?
- How do you prove that tan(x/2)=(secx)/(secxcscx+cscx) ?
- How to solve for x when restricted to interval [0,2pi] tan(x/2)=(2-sqrt(2))/2sinx?
- I need some help figuring out how to prove # cos^2x = (1+cos(2x))/2# ? (the x isn’t part of the exponent but I’m not sure how to signal that when typing) Thanks!
- How do you solve for #A# in this question: #0 <= A <= 360: 2(cosA)^2 + 5sinA - 4 =0#?
- Verify the identity of #sec^6X(secXtanX)-sec^4X(secXtanX)=sec^5Xtan^3X ?#
- Sin^4x -cos^4x= cos3x Could you solve this?
- If #tan(cos^-1x) = sin(cot^-1 1/2)#, what is #x#?
- How could I prove that this is true?