Elijah Alexander
Trigonometry teacher | Verified Expert
I hold a degree in Trigonometry from McDaniel College, where I honed my passion for unraveling the intricacies of angles and functions. With a deep-rooted understanding of trigonometric principles, I am committed to guiding students through the maze of sine, cosine, and tangent. My mission is to illuminate the path to mastery in this pivotal field of mathematics, making concepts clear and accessible. Whether it's solving triangles or navigating through identities, I am here to empower students to conquer Trigonometry with confidence and clarity. Let's embark on this mathematical journey together!
Questions
How do you find two solutions (in degree and radians) for cscx = (2sqrt3)/3?
A fire is spotted 29 degrees west of South. The fire is 58 km from the look out station. A fire fighting base is 62 km due west of the first station. How far is the fire from the fighting base?
How do you evaluate #Sin(pi/2) + 6 cos(pi/3) #?
How do you solve the triangle given #trianglePQR, p=12, mangleQ=80, mangleR=30#?
How do you evaluate #cos((6pi)/5)#?
How do you simplify using the half angle formula #sin(22^o 30')#?
How do you graph #h(x) = 2 sin(πx−3π) − 4#?
How do you solve #cosx-4=sinx-4# for #0<=x<=2pi#?
How do you graph #r=1-cosx#?
How do you evaluate the expression #cos(u+v)# given #cosu=4/7# with #0<u<pi/2# and #sinv=-9/10# with #pi<v<(3pi)/2#?
How do you prove #cos(2x) = [cos(x)]^2 - [sin(x)]^2# and #sin(2x) = 2sin(x)cos(x)# using Euler's Formula: #e^(ix) = cos(x) + isin(x)#?
Sec thita -1÷ sec thita +1 =(sin thita ÷ 1+ costhita)^2 ?
How do you evaluate #tan(arccos(-1/3))#?
How do you find the exact value of #arccos (-sqrt3/2)#?
How do you convert #y = sqrt(3)x# into polar form?
How do you solve the triangle given α = 15.6 degrees, b = 10.25, and c = 5.5?
X=a(cosθ+cos2θ),y=b(sinθ+sin2θ) Remove θ By applying Elimination Methods ??
How do you find the remaining trigonometric functions of #theta# given #sectheta-=13/5# and #sintheta<0#?
How do you multiply # (4-5i)(2+7i) # in trigonometric form?
How do you evaluate #arcsec (sec(-pi/3))#?