# Chloe Alexander

Bellevue University

Precalculus

Precalculus teacher | Experienced educator in USA

I hold a degree in Precalculus from Bellevue University, where I honed my passion for mathematics. With years of experience, I specialize in simplifying complex precalculus concepts, making them accessible and enjoyable for students. My approach focuses on fostering a deep understanding of mathematical principles through personalized instruction and real-world applications. Whether it's trigonometry, functions, or algebraic concepts, I'm here to guide students towards mastery and success. Let's embark on this mathematical journey together and unlock your full potential in precalculus!

## Questions

- How do you solve #81x ^ { - 4} - 323x ^ { - 2} - 4= 0#?
- What are the equations of the horizontal asymptotes of the graph?
- How do you solve #e^ { 2x } \geq 5#?
- How do you solve #\log ( x + 1) + \log ( x + 2) = 1#?
- How do you simplify #(6+i)/(6-i)#?
- How do you divide #(3b ^ { 5} - 9b ^ { 4} + 3b ^ { 2} ) -: 6b ^ { 2}#?
- A circle in the #xy# plane has equation #(x+92)^2 + (y+54)^2 = 73#. What is the length of the diameter of the circle?
- If a function admits horizontal asymptote at #-oo# but at #+ oo# does not admit,she can admit oblique asymptote to #+ oo#?
- We have #f=X^3-3X^2+1#;How to find #x_1^(-4)+x_2^(-4)+x_3^(-4)#?; #x_1,x_2,x_3# are roots of #f(x)=0#.
- How many times do you have to square #2# for it to become a multiple of #3#? Is it possible? In algebraic terms, #2^x =3y#.
- How do you solve #\frac { 2^ { x } } { 1- 2^ { x } } = 3#?
- What is the inverse of #y=4^(2x+4)#?
- How do you solve #2e ^ { 2x + 1} = 0#?
- How do you multiply #(7i ) ( - 3i ) ( 8+ 2i ),# assuming #i# is an imaginary number?
- How do you graph #7x ^ { 2} - 5y ^ { 2} - 35= 0#?
- How do you solve #5+ 20\cdot 2^ { 2- 3x } = 10\cdot 2^ { - 2x } + 5#?
- What is the quotient #( x ^ { 3} + 3x ^ { 2} + 5x + 3) \div ( x + 1) #?
- How do you find the remainder when #x^5-2x^4-3x^3+4x^2+3x+6# is divided by #x-1#?
- Does #f(x) = x^7+2x^6+3x^5+4x^4+5x^3+6x^2+7x+8# have at least one real root?
- How do you simplify #(- 2+ 8i ) + ( - 3+ 7i )#?