You spend #1/2# of your allowance each week on school lunches. Each lunch cost $1.25. How much is your weekly allowance?
All told, our weekly allowance is:
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To find your weekly allowance:
- Let ( x ) be your weekly allowance.
- You spend ( \frac{1}{2} ) of your allowance on school lunches, which is ( \frac{1}{2}x ).
- Since each lunch costs $1.25, you spend ( \frac{1}{2}x ) on lunches, which equals ( 1.25 \times \frac{1}{2}x ).
- Setting this equal to your allowance, we have the equation: ( 1.25 \times \frac{1}{2}x = x ).
- Solve for ( x ) to find your weekly allowance.
[ 1.25 \times \frac{1}{2}x = x ]
[ 0.625x = x ]
[ 0.625x - x = 0 ]
[ -0.375x = 0 ]
[ x = 0 ]
So, your weekly allowance is $0. However, this result seems incorrect. Let's reevaluate the problem.
Given that you spend ( \frac{1}{2} ) of your allowance, which we'll denote as ( x ), on school lunches, and each lunch costs $1.25:
- ( \frac{1}{2}x ) is spent on lunches weekly.
- Since ( \frac{1}{2}x ) equals the cost of the lunches, we have: ( \frac{1}{2}x = 1.25 ).
- Solve for ( x ) to find your weekly allowance.
[ \frac{1}{2}x = 1.25 ]
[ x = 1.25 \times 2 ]
[ x = 2.50 ]
Thus, your weekly allowance is $2.50.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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