You place a block of wood into a beaker of water and it floats. What can you say about the buoyant force on the block?

Answer 1

The buoyant force is stronger than the gravity force (the block's weight). Consequently, the block's density is smaller than water's density.

According to Archimedes' principle, any body immersed in a fluid—such as water—will feel an upward force equivalent to the weight of the fluid that it has displaced.

In terms of math,

buoyant force #= F_b = V_b *d_w*g# #V_b = # body volume #d_w = # water density #g = # gravity acceleration
while the weight #W= V_b*d_b*g#
#d_b= body density#
As the body floats #=> F_b > W => d_w>d_b#
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Answer 2

The buoyant force on the block is equal to the weight of the water displaced by the block, which is greater than the weight of the block, causing it to float.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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