You need to separate water from salt in a saltwater mixture. Why would it not work to filter the mixture?

Answer 1

Because the salt and the water form an homogeneous solution...

The act of dissolution in this scenario is to all intents and purposes a chemical reaction... Bonds and broken, and new substances are formed. We start with solid salt...we end with a solution of aquated ions...

#NaCl(s) stackrel(H_2O)rarrunderbrace([Na(OH_2)_6]^+ + [Cl(H_2O)_4]^-)# #" AQUATED IONS, i.e. NaCl(aq)"#
The sodium ions, and chloride ions, coordination complexes if you like, remain in solution. There is no solid to separate by filtration. Ethanol could be added to the solution, and this would precipitate much of the solute as #NaCl(s)#.

Alternatively, the solution could be boiled, and the water vapour condensed to give more or less pure water.....

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Answer 2

Filtering would not work to separate water from salt in a saltwater mixture because salt dissolves in water, forming a homogeneous solution. Since salt particles are dissolved at the molecular level, they are too small to be filtered out by a typical filter, which can only separate solid particles from liquids in a heterogeneous mixture.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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