# You have two similar triangles. The first triangle has a height of 10 and an area of 40. If the second triangle is twice as tall, how much area does it cover?

Area of second triangle is

In two similar triangles sides are proportional

and areas of triangles have the ratio which is square of ratioof sides

Hence ss second triangle is twice as tall

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Since the second triangle is twice as tall as the first triangle, its height is 20. Since the triangles are similar, the ratio of their heights is the same as the ratio of their areas. Therefore, the area of the second triangle is (40 \times \left(\frac{20}{10}\right)^2 = 160). Thus, the second triangle covers an area of 160 square units.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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