# You have studied the number of people waiting in line at your bank on Friday afternoon at 3 pm for many years, and have created a probability distribution for 0, 1, 2, 3, or 4 people in line. The probabilities are 0.1, 0.3, 0.4, 0.1, and 0.1, respectively. What is the probability that at most 3 people are in line at 3 pm on Friday afternoon?

There could be three persons in line at most.

Using the compliment rule would make this question simpler, though, as you can simply deduct the value you are not interested in from the total probability.

as:

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To find the probability that at most 3 people are in line at 3 pm on Friday afternoon, we sum the probabilities of having 0, 1, 2, or 3 people in line:

P(at most 3 people) = P(0 people) + P(1 person) + P(2 people) + P(3 people) = 0.1 + 0.3 + 0.4 + 0.1 = 0.9

Therefore, the probability that at most 3 people are in line at 3 pm on Friday afternoon is 0.9.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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