# Y varies inversely with twice the value of x. When y = 8, x = 2. How do you find y when x = 8?

To find y when x = 8, we can use the inverse variation equation.

First, we need to determine the constant of variation. In this case, y varies inversely with twice the value of x, so the constant of variation is 2.

Next, we can set up the inverse variation equation: y = k/(2x), where k is the constant of variation.

To find the value of k, we can substitute the given values of y and x into the equation: 8 = k/(2*2).

Simplifying the equation, we have: 8 = k/4.

To solve for k, we can multiply both sides of the equation by 4: 32 = k.

Now that we have the value of k, we can substitute it back into the inverse variation equation: y = 32/(2x).

To find y when x = 8, we substitute x = 8 into the equation: y = 32/(2*8).

Simplifying the equation, we have: y = 32/16.

Therefore, when x = 8, y = 2.

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So our equation becomes:

This is the same as:

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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